Gas X is obtained by the reaction of copper with dilute nitric acid, The obtained gas is oxidized to brown gas I, when reacts with oxygen. The gas I is soluble in water and its aqueous solution is Z. X Y and Z respectively are

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NO, N₂O and HNO₃

N₂O, NO and HNO₂

NO, NO₂ and HNO₃

NO₂, NO and HNO₃

answer is A.

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Detailed Solution

$3Cu+8 {HNO}_{3} (dil .)\to3 Cu {({NO}_{3})}_{2} + \underset{' X'}{2 NO} + 4 H_{2} O 2 NO + O_{2} ⇌ \underset{Y}{2 {NO}_{2}}$
$\underset{Y}{3 {NO}_{2}} + H_{2} O ⟶ \underset{Z}{2 H {NO}_{3}} + \underset{X}{NO}$

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