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Gaseous compound X-contains 44.4% carbon 51.9% nitrogen and 3.7% hydrogen. Under similar conditions 50cc of x is diffused through a porous plug in 25sec and same volume of hydrogen diffused in 6.8 sec, the molecular formula of “X” is

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HCN

CH₃NH₂

${CH}_{3} {NO}_{2}$

$P h C N$

answer is A.

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Detailed Solution

[Step-1] : $C = \frac{44.4}{12} = 3.7 \Rightarrow 1$

$N = \frac{51.9}{14} = 3.7 \Rightarrow 1$

$H = \frac{3.7}{1} = 3.7 \Rightarrow 1$

Formula :HCN

[Step-2]: $\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} = \frac{V_{1}}{t_{1}} \times \frac{t_{2}}{V_{2}}$

$\sqrt{\frac{M_{2}}{M_{1}}} = \frac{6.8}{25}$

$M_{1} = 27 \Rightarrow H C N$

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