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Q.

Gaseous mixture contains 56 g of N2, 44 g of CO2 and 16g of CH4. The total pressure of mixture is 720 mm of Hg . The partial pressure of methane is

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a

75 atm

b

160 atm

c

180 atm

d

215 atm

answer is C.

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Detailed Solution

First of all we have to calculate the number of moles.
Number of moles of N2 = 5628 = 2
Number of moles of CO24444 = 1
Number of moles of CH41616  = 1
 Total number of moles = 2+1+1 = 4
 mole fraction of CH414
 partial pressure of CH4
= mole fraction of CH4× total pressure =14×720=180atm

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