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Q.

 ∆Gf° for the formation of  HI(g) from its gaseous elements is -9.67kJ/mol at 500 K. When the partial pressure of HI is 10.0 atm and of I2  is 0.001 atm. what must be the partial pressure of hydrogen at this temperature to reduce the magnitude of the reaction to zero?

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a

103 atm 

b

10-3 atm 

c

1 atm 

d

10 atm

answer is A.

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Detailed Solution

12H2+12I2→HI,ΔGf0=-9.67 kJ/mol  If ΔG=0, then Keq=Q·(Q= reactionquotient )  Nowfrom ΔGf0=-RTlnKeq ⇒9.67=8.314×5001000lnKeq⇒Keq=10 ⇒10=PHIPH212PI212

PH2=100100×10-3=103 atm

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