Give an illustration of a property that cannot be calculated using the Biot-Savart law.

Biot-Savart’s law is an equation that gives the magnetic field produced due to a current-carrying segment.

Biot-Savart  Law states that magnetic intensity dB at a point P due to current I flowing through a small element dl is,

a) Directly proportional to the current (I).

b) Directly proportional to the length of the element (dl).
c) Directly proportional to the sine of angle θ between the direction of current and the line joining the element dl from a point P.

d) Inversely proportional to the square of the distance (r) of a point P from the element dl.

Considering all the above points and we can write the formula as: 
$dB \alpha \frac{I dl \sin \theta }{r^2}$
$dB = K \frac{Idl \sin \theta }{r^2}$
$K = \frac{{\mu }_0{\mu }_r}{4\pi }$
${\mu }_0$ = Absolute permittivity of air in a vacuum
${\mu }_r$= relative permittivity.
From the formula, we can say that the biot savart law does not explain electric field intensity because the electric field intensity tells us about the magnitude and direction of the force experienced by the charged particle.