Give EAN value of Mg in${\left[\mathrm{Mg}\right(\mathrm{EDTA}\left)\right]}^{2-}:$

E.A.N. = Atomic no. of central metal ion − oxidation no. of central metal ion + 2× coordination no. of central metal ion.
 [Mg(EDTA)]²⁻     
+2
  EAN = 10+6×2  = 22
 EDTA is hexadentate.