Give the correct of initials T or F for following statements. Use T if statement is true and F if it is false.(I) Co(IIl) is stabilised in presence of weak field ligands, while Co(II) is stabilised in presence of strong field ligand.(II) Four coordinated complexes of Pd(II) and Pt(II) are diamagnetic and square planar.(III) Ni(CN)44− ion and Ni(CO)4 are diamagnetic tetrahedral and square planar respectively.(Iy) Ni2+ ion does not form inner orbital octahedral complexes.

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Give the correct of initials T or F for following statements. Use T if statement is true and F if it is false.
(I) Co(IIl) is stabilised in presence of weak field ligands, while Co(II) is stabilised in presence of strong field ligand.
(II) Four coordinated complexes of Pd(II) and Pt(II) are diamagnetic and square planar.
(III) ${[Ni (CN)_{4}]}^{4 -} ion and [Ni (CO)_{4}]$ are diamagnetic tetrahedral and square planar respectively.
(Iy) Ni²⁺ ion does not form inner orbital octahedral complexes.

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answer is D.

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Detailed Solution

$(I) Both {CO}^{2 +} and {Co}^{3 +} are stabilized in the presence of strong field ligands due to higher CFSE values.$
$(II) Because of higher Z_{eff} value on the valence shell of {Pd}^{2 +} and {Pt}^{2 +} cations they, always from inner orbital complex.$
$(III) [Ni (CO)_{4}]; {sp}^{3}, tetrahedral, μ = 0 BM {[Ni (CN)_{4}]}^{4 -}; {sp}^{3}, tetrahedral, μ = 0 BM$
$(IV) {Ni}^{2 +} in the octahedral field.$