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Q.

Give the equation for the value of g at depth “d” from the surface of Earth. What is the value of “g” at the centre of Earth.

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Detailed Solution

Acceleration due to gravity at a depth "d" from the surface of earth:

$g_{d} = g (1 - \frac{d}{R})$

at centre of the earth: d = R
so, $g_{d} = g (1 - \frac{d}{d}) = 0$

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