Give the preparation of a) XeOF4 b) XeO2F2

a) Preparation of XeOF4: XeOF4 can be prepared by partial hydrolysis of XeF6.XeF6+H2O→XeOF4+2HFb) Preparation of XeO2F2: XeO2F2 can be prepared by partial hydrolysis of XeF6 XeF6+2H2O→XeO2 F2+4HF

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Give the preparation of a) XeOF₄ b) XeO₂F₂

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Detailed Solution

a) Preparation of XeOF₄: XeOF₄ can be prepared by partial hydrolysis of XeF₆.
${XeF}_{6} + H_{2} O \to {XeOF}_{4} + 2 HF$
b) Preparation of XeO₂F₂: XeO₂F₂ can be prepared by partial hydrolysis of XeF₆
${XeF}_{6} + 2 H_{2} O \to {XeO}_{2} F 2 + 4 HF$