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Q.

Given : A circle, 2x2 + 2y2 = 5 and a parabola y2=45x

Statement-1: An equation of a common tangent to these curves is y=x+5

Statement-2: If the line y=mx+5m(m0) is their common tangent, then m satisfies m43m2+2=0

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a

Statement-1 is false, Statement-2 is true, 

b

Statement-1 is true, Statement-2 is true,
Staternent-2 is a correct explanation for Statement-1.

c

Statement-1 is true, Statement-2 is false

d

Statement-1 is true, 'Staternent-2 is true,
Statement-2 is not a correct explanation for Statement-1.

answer is A.

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Detailed Solution

Let a tangent to the parabola be

y=mx+5m(m0)

As it is a tangent to the circle x2+y2=5/2 we have 

5m=521+m21+m2m2=2

which gives m4+m22=0m21m2+2=0

As mR,m2=1  m=±1

Also m=±1 does satisfy m43m2+2=0

Hence common tangents are

y=x+5 and y=x5

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