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Given : The mass of electron is 9.11 x 10^-31 kg, Planck constant is 6.626 x 10^-34 Js, the uncertainty involved in the measurement of velocity within a distance of 0.1 A^o is:

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5.79 x 10⁵ m s^-1

5.79 x 10⁸ m s^-1

5.79 x 10⁶ m s^-1

5.79 x 10⁷ m s^-1

answer is C.

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Detailed Solution

$Δv \cdot Δx = \frac{h}{4 πm} Δv = \frac{6 .626 \times 10^{- 34}}{4 \times 3 .14 \times 9 .11 \times 10^{- 31} \times 0 .1 \times 10^{- 10}} = 5 .8 \times 10^{6} m / \sec$

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