Given 5 different green dyes, 4 different blue dyes and 3 different red dyes, the number of combinations of dyes taking atleast one green dye and one blue  dye is ,

The number of subsets of the set of green dyes IS  $2^5-1=31$ The number of subsets of the set of blue dyes is$2^4-1=15$ The number of subsets of the set of red dyes 1s $2^3=8$ The desired number= 31 · 15 · 8 = 3720