Q.

Given  a,b{0,1,2,3,......,19,20}, consider the system of equations
x + y + z = 4
2x + y + 3z = 6
x + 2y + az = b
Let
P denotes number of order pairs (a, b) so that system of equations has a unique solution.
Q denotes number of ordered pairs (a, b) so that system of equations has no solution.
R denotes number of ordered pairs (a, b) so that system of equations has infinite solutions, then (P + Q + R) is:

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answer is 441.

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Detailed Solution

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 D=a,D1=2(ab+6)
D2=2ab+6,D3=6b 
For unique solution,  b0
 L=20×21=420
For no solution,   a=0,b6,
 M=1×20=20
For infinitely many solutions.
a = 0, b = 6, N = 1×1=1

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