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Given a force of $50 N$ acts on a body and moves it through a distance of $4 m$ on a horizontal surface. The work done is [[1]] $Joules$ if the direction of force is at an angle of $60^{°}$ to the horizontal surface.

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Detailed Solution

Given a force of

50 N

acts on a body and moves it through a distance of

4 m

on a horizontal surface. The work done is

100 Joules

if the direction of force is at an angle of

60^{°}

to the horizontal surface.
Work is defined as “the energy transferred to or from an object via the application of force along a displacement.” It is a product of force

(F)

applied in the direction of movement and displacement

(s)

. Mathematically, Work

(W)

is represented as

W = F scosθ

where,

θ

is the angle between force applied and displacement caused.
Given:
Force

F = 50 N

Distance

s = 4 m

Angle

θ = 60^{°}

Therefore,

W = 50 \times 4 \times 1 / 2

(since

\cos 60^{°} = ½)

W = 100 J

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