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Q.

Given a number of capacitors labelled as 8µF , 250V. Find the minimum number of capacitors needed to get an arrangement equivalent to 16µF,1000V

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a

16

b

64

c

32

d

4

answer is C.

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Detailed Solution

n = 1000/250 = 4 ; $m = \frac{16}{8 / 4} = 8$
$N = nm = 4 \times 8 = 32$

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