Given a triangle ABC with side AB = 8 cm. To get a line segment BB' = $\frac{3}{4}$ of AB, in what ratio does the line segment AB be divided?

Given: AB = 8 cm

BB' = $\frac{3}{4} \mathrm{of} \mathrm{AB} = \frac{3}{4} \times 8 = 6 \mathrm{cm}$

Now, AB' = AB − BB'

⇒ AB' = 8 cm − 6 cm

⇒ AB' = 2 cm

Then, BB' : AB' = 6 : 2 = 3 : 1

Hence, required ratio = 3 : 1