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Given at 350 K $p_{A}^{o} = 300$ torr and $p_{B}^{o} = 800$ torr, the composition of the mixture having a normal boiling point of 350 K is:

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$X_{A} = 0.08$

$X_{A} = 0.02$

$X_{A} = 0.04$

$X_{A} = 0.06$

answer is A.

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Detailed Solution

$760 = 300 X_{A} + 800 (1 - X_{A})$

$760 = 300 X_{A} + 800 - 800 X_{A} 800 X_{A} - 300 X_{A} = 40 500 X_{A} = 40$

$\Rightarrow 500 X_{A} = 40$

$∴ X_{A} = \frac{40}{500} = 0 .08$

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