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Given BC = 5p - 2 cm, QR = 6p cm, AC = 4 cm, PR = 8 cm. If ∆ ABC ~ ∆PQR, find BC

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Detailed Solution

$\frac{A B}{P Q} = \frac{B C}{Q R} = \frac{A C}{P R} \frac{5 p - 2}{6 p} = \frac{4}{8} \frac{5 p - 2}{6 p} = \frac{1}{2} 10 p - 4 = 6 p 4 p = 4 p = 1 B C = 5 p - 2 = 5 (1) - 2 = 3 B C = 3$

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