Given below are half cell reactions 
${{\mathrm{MnO}}_4}^{-}+8{\mathrm{H}}^{+}+5{\mathrm{e}}^{-}\mathrm{\hspace{0.17em}}\to \mathrm{\hspace{0.17em}\hspace{0.17em}}{\mathrm{Mn}}^{2+}+4{\mathrm{H}}_2\mathrm{O}\mathrm{\hspace{0.17em}\hspace{0.17em}}; {\mathrm{E}}_{{{\mathrm{MnO}}_4}^{-}/{\mathrm{Mn}}^{+2}}^{\mathrm{o}}=1.510\mathrm{V}$
$\frac{1}{2}{\mathrm{O}}_2+2{\mathrm{H}}^{+}+2{\mathrm{e}}^{-}\to \mathrm{\hspace{0.17em}}{\mathrm{H}}_2\mathrm{O}; {\mathrm{E}}_{{\mathrm{O}}_2/{\mathrm{H}}_2\mathrm{O}}^{\mathrm{O}}=1.223\mathrm{V}$
will the permanganate ion liberate O₂ from water in the presence of an acid?