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Given below are the quantum numbers for 4 electrons.
A. n = 3, l = 2, m= 1, m= +1/2
B. n = 4, l = 1, m= 0, m= +1/2
C. n = 4, l = 2, m= –2, m= –1/2
D. n = 3, l = 1, m= –1, m= +1/2
The correct order of increasing energy is :

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D < B < A < C

D < A < B < C

B < D < A < C

B < D < C < A

answer is B.

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Detailed Solution

Greater the value of (n+l)greater is energy. If the value of n +l comes out to be same, then the greater value of n is preferred.
Therefore, the correct order of energy is-
D < A < B < C

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