Given below are two statements :
Statement I : If the Brewster’s angle for the light propagating from air to glass is ${\mathrm{\theta }}_{\mathrm{B}}$ . Then the Brewster’s angle for the light propagating from glass to air is $\frac{\mathrm{\pi }}{2}-{\mathrm{\theta }}_{\mathrm{B}}$.
Statement II : The Brewster’s angle for the light propagating from glass to air is ${\tan }^{-1}\left({\mathrm{\mu }}_{\mathrm{g}}\right)$ where $\left({\mathrm{\mu }}_{\mathrm{g}}\right)$ is the refractive index of glass.
In the light of the above statements, choose the correct answer from the options given below :