Given below are two statements:
Statement-I : Cis-But-2-ene has less dipole moment than trans-but-2-ene.
Statement-II : $\mathrm{R}-\mathrm{C}\equiv \mathrm{C}-{\mathrm{R}}^{\text{'}}$  reacts with ${\mathrm{H}}_2$  in presence of $\mathrm{Na}\text{/}\mathrm{liq}.{\mathrm{NH}}_3$  to form cis-alkene.
In the light of the above statements, choose the most appropriate answer from the options given below:

Trans has no (or zero) dipole moment than cis isomer.
Cis isomer has more dipole moment than trans isomer, because it has two similar groups on same side of double bond. So the dipole gets added, thus cis isomer is more polar than trans.
In the trans isomer, the terminal groups are on the opposite sides of the double bond. So, here the dipole moments of the trans isomer is zero.

$\mathrm{R}-\mathrm{C}\equiv \mathrm{C}-{\mathrm{R}}^{\text{'}}$  reacts with ${\mathrm{H}}_2$  in presence of $\mathrm{Na}\text{/}\mathrm{liq}.{\mathrm{NH}}_3$  to form trans-alkene.