Given below are two statements :
Statement-I : The conversion proceeds well in the less polar medium.
${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{Cl}\stackrel{{\mathrm{HO}}^{-}}{\to }{\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{OH}+{\mathrm{Cl}}^{-}$
Statement-II : The conversion proceeds well in the more polar medium.

In the light of the above statements, choose the correct answer from the options given below.

$$\begin{gathered} {\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{Cl}+\stackrel{\ominus }{\mathrm{O}}\mathrm{H} \\ \mathrm{Reactant} (\mathrm{higher} \mathrm{charge} \mathrm{density}) \end{gathered}$$

Transition state (less charge density)
$\Rightarrow$ This reaction will proceed faster in less polar medium which will not increase the activation energy value.

$$\begin{gathered} {\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{Cl}+{\mathrm{R}}_3\mathrm{N} \\ \mathrm{Reactant} (\mathrm{low} \mathrm{charge} \mathrm{density}) \end{gathered}$$

Transition state (Higher charge density)

$\Rightarrow$ This reaction will proceed faster in more polar medium which will decrease the activation energy value.