Given below are two statements.

Statement I : CO and NO have same bond order.
Statement II : Central atoms in $N{O}_2^{-}$  and $B{F}_3$  have same hybridization.
 

In the light of the above statements, choose the most appropriate answer from the options given below .

Statement I is incorrect, but statement II is correct

The species that have same number of electrons have same bond order. CO and NO have different bond order.
Number of electrons in CO = 6 + 8 = 14
Number of electrons in NO = 7 + 8 = 15

${\mathrm{NO}}_2^{-}$ and $B{F}_3$  have same hybridization, i.e. $s{p}^2$

${\mathrm{NO}}_2^{-}\Rightarrow 2\sigma +1lp=3,\text{i.e. }s{p}^2-$hybridized.

$B{F}_3\Rightarrow 3\sigma +0lp=3$  i.e. $s{p}^2$  - hybridized.