Given below are two statements
StatementI(S-I) : The limiting molar conductivity of KCl(strong electrolyte) is higher compared to that of $C H_{3} C O O H$ (weak electrolyte).
StatementII(S-II) : Molar conductivity decreases with decrease in concentration of electrolyte.
In the light of the above statements, choose the most appropriate answer from the options given below.

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S-I is false and S-II is true

S-I is true and S-II is false

Both S-I & S-II are true.

Both S-I and S-II are false

answer is D.

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Detailed Solution

$\begin{array}{l} \overset{O}{Λ_{M}} K C l = \overset{O}{Λ_{M}} (K^{+}) + \overset{O}{Λ_{M}} (C l^{-}) \end{array}$
$= 73.55 {scm}^{2} / mol + 76.35 {scm}^{2} / mol = 149.3 {scm}^{2} / mol$
$\begin{array}{l} \overset{O}{Λ_{M}} C H_{3} C O O H = \overset{O}{Λ_{M}} (C H_{3} C O O^{-}) + \overset{O}{Λ_{M}} (H^{+}) \end{array}$
$= 40.9 {scm}^{2} / mol + 349.8 {scm}^{2} / mol = 390.7 {scm}^{2} / mol$
$∴ Λ_{M}^{o} of {CH}_{3} COOH is more than KCl . Hence statement I is false.$
As the concentration of electrolyte decreases, molar conductivity increases $(Λ_{M} = \frac{K \times 1000}{M})$ Hence statement II is also false.

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