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Q.

Given below is unbalanced chemical equation,
$a AgN O_{3} + b Cu \to c Cu (N O_{3})_{2} + d A g$
What is the value of 'a' in the above given chemical equation after balancing the chemical equation?

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answer is 2.

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Detailed Solution

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In the given reaction, $N O_{3}$ is not balanced. Hence, multiply by 2 to $AgN O_{3}$
$2 AgN O_{3} + Cu \to Cu (N O_{3})_{2} + Ag$
Multiply by 2 to Ag on the product side to balance the Ag element,
$2 AgN O_{3} + Cu \to Cu (N O_{3})_{2} + 2 Ag$
Balancing both the sides with equal moles reactant and product.

$Ag = 1 \times 2$ $= 2$	$Ag = 1 \times 2$ $= 2$
$N = 1 \times 2$ $= 2$	$N = 2$
$O = 3 \times 2$ $= 6$	$O = 6$
$Cu = 1$	$Cu = 1$

Hence, the balanced chemical reaction equation is,

$2 AgN O_{3} + Cu \to Cu (N O_{3})_{2} + 2 Ag$

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Given below is unbalanced chemical equation,a AgNO3+ b Cu→c Cu(NO3)2+ d AgWhat is the value of 'a' in the above given chemical equation after balancing the chemical equation?