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Given C + 2S → CS₂, $large Delta H_f^0$ =+117.0 kJ mol^–1
C + O₂ → CO₂, $large Delta H_f^0$ = – 393.0 kJmol–1
S + O₂ → SO₂, $large Delta H_f^0$ = – 297.0 kJmol–1
The heat of combustion of CS₂ + 3O₂ → CO₂ + 2SO₂ is

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-807 KJ mol^-1

-1104KJ mol^-1

+1104KJ mol^-1

+807 KJ mol^-1

answer is B.

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Detailed Solution

begin{array}{l} {Delta _C}H(C{S_2}) = [{Delta _f}H(C{O_2}) + 2{Delta _f}H(S{O_2})] - [{Delta _f}H(C{S_2}) + 3{Delta _f}H({O_2})\ ,,,,,,,,,,,,,,,,,,,,,,,,,, = [ - 393 + 2( - 297)] - [ + 117 + 3(0)]\ ,,,,,,,,,,,,,,,,,,,,,,,,,, = - 393 - 594 - 117 = - 1104KJ/mole end{array}

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