Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

 Given C + 2S → CS2large Delta H_f^0=+117.0 kJ mol–1
C + O2 → CO2, large Delta H_f^0 = – 393.0 kJmol–1
S + O2 → SO2, large Delta H_f^0  = – 297.0 kJmol–1
The heat of combustion of CS2 + 3O2 → CO2 + 2SO2 is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

-807 KJ mol-1

b

-1104KJ mol-1

c

+1104KJ mol-1

d

+807 KJ mol-1

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

begin{array}{l} {Delta _C}H(C{S_2}) = [{Delta _f}H(C{O_2}) + 2{Delta _f}H(S{O_2})] - [{Delta _f}H(C{S_2}) + 3{Delta _f}H({O_2})\ ,,,,,,,,,,,,,,,,,,,,,,,,,, = [ - 393 + 2( - 297)] - [ + 117 + 3(0)]\ ,,,,,,,,,,,,,,,,,,,,,,,,,, = - 393 - 594 - 117 = - 1104KJ/mole end{array}

 

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon