Given four points such that no three of them are collinear, then the number of lines that can be drawn through them is

Number of lines that can be drawn through n points$=\frac{n\left(n-1\right)}{2}$

(no three points are collinear)

Number of lines through 4 points $=\frac{4\left(4-1\right)}{2}$

$=\frac{4\left(3\right)}{2}$ $=2\times 3$ $=6$