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Given lines l1,l2 and l3 in fig. 2 are parallel. The value of x is

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$120 °$

$140 °$

$30 °$

$90 °$

answer is C.

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Detailed Solution

l₁∣∣ l₃ and l₄ is transversal line.

$\Rightarrow$ ∠1 = 40 $°$ (Corresponding angles)

Now ∠x + ∠1 = 180 $°$ (Angles made on the same line )

⇒ ∠x + 40 $°$ = 180 $°$

⇒ ∠x = 180 $°$ − 40 $°$

⇒ ∠x = 140 $°$

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