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Q.

Given mass number of gold = 197, density of gold = 19.7g cm–3, Avogadro’s number = 6 × 1023. The radius of the gold atom is approximately.

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a

1.5 × 10–10 m

b

1.5 × 10–8 m

c

1.5 × 10–9 m

d

1.5 × 10–12 m

answer is C.

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Detailed Solution

m=(vol)(density)
A×mp=43πr3×( den ) 197×1.67×1027=43×3.14r3×19.7×103 r3=1.67×34×3.14×1030r3=4×1030 r1.5×1010m

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