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Q.

Given P V = K (constant) we can say that

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a

$\frac{d P}{p} = \frac{d V}{V}$

b

$\frac{d P}{p} = \frac{- d V}{V}$

c

$\frac{d P}{p} = \frac{2 d V}{V}$

d

$\frac{d P}{p} = \frac{- 1}{2} \frac{d V}{V}$

answer is B.

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Detailed Solution

P V = K

$\frac{d}{d t} (P V) = \frac{d}{d v} (K)$

$P \times \frac{d v}{d t} + v \frac{d P}{d v} = 0$

$P \times d v = - v d p$

$\frac{d P}{p} = \frac{- d v}{v}$

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