Q.

Given: r = R0A, where r is the radius of nucleus of mass no. A and R0 is a constant whose value is equal to 1.5 × 101-15 metre. (Given 1 amu = 1.66 × 10-15 g)
What is the density of a nucleus of mass number A?

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a

1.17×1017kg/cm3

b

1.17×1017kg/m3

c

43π1.5×10153A

d

None of these

answer is B.

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Detailed Solution

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r=R0A1/3

 Volume of nucles (4/3)πr3

=43π1.5×10153m3 density d=mV=1.66×1027kg4/3×3.141.5×10153=1.17×1017kg/m3

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