Q.

Given standard electrode potentials :

Fe3++3e Fe;Eº=0.036 volt

Fe2++2e Fe;Eº=0.440 volt

The standard electrode potential E0 for Fe3++e Fe2+

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a

0.440   volt

b

0.404   volt

c

0.476   volt

d

0.772   volt

answer is D.

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Detailed Solution

EFe3+/Fe2+0=3×EFe3+/Fe02×EFe2+/Fe0

=3×0.0362×0.44V

= 0.772 V

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