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Q.

Given standard electrode potentials
Fe2+ + 2e → Fe; Eº = – 0.44 V
Fe3+ + 3e → Fe; Eº = – 0.036 V
The standard electrode potential (Eº) for
Fe3+ + e– → Fe2+ is

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a

+ 0.772 V

b

– 0.476 V

c

– 0.404 V

d

0.404 V

answer is D.

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Detailed Solution

=(0.036×3)-0.88=0.772v

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