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Q.

Given that a,b,c  are integers such that abc=60  and ω  is  a non real cube root of unity. Then the minimum possible value of  |a+bω+cω2| is

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a

3

b

3

c

2

d

1

answer is B.

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Detailed Solution

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 |a+bω+cω2|2=(a+bω+cω2)(a+bω2+cω) =a2+b2+c2abbcca =12((ab)2+(bc)2+(ca)2)   
Now to minimize, choose  a=3,b=4,c=5.

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