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Given that the abundance of the isotopes $^{54} Fe,^{56} Fe &^{57} Fe$ are 5%, 90% and 5% respectively, the atomic mass of ‘Fe’ is

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58.85

55.95

55.75

55.05

answer is C.

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Detailed Solution

$Atomic mass = \frac{54 \times 5 + 56 \times 90 + 57 \times 5}{100}$
= 55.75 Average atomic mass.

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