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Q.

Given that the position of the body in m is a function of time as follows: x = 2t4+5t+4

The mass of the body is 2 kg. What is the increase in its kinetic energy one second after the start of motion?

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a

169 J

b

144 J

c

168 J

d

32 J

answer is D.

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Detailed Solution

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x = 2t4+5t+4    ⇒  v = dxdt = 8t + 5

at t = 0, v = 5 m/s

at t = 1 s, v = 8 ×1+5 = 13 m/s

Increases in KE = 12m[132-52] = 144 J

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