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Given that the standard potentials $(E^{0})$ of $C u^{2 +} / C u$ and $C u / C u^{+}$ are 0.34 V and -0.522 V respectively, the $E^{0}$ of $C u^{2 +} / C u^{+}$ is:

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$- 0.158 V$

$0.182 V$

$- 0.182 V$

+0.158 V

answer is D.

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Detailed Solution

${Cu}^{+ 2} + 2 e^{-} \to Cu E^{0} = 0.34 Cu \to {Cu}^{+} + e^{-} E^{0} = 0.522 {Cu}^{+ 2} + e^{-} \to {Cu}^{+} E^{0} = ? {nE}^{0} = n_{1} E_{1}^{0} + n_{2} E_{2}^{0} = 2 \times 0.34 + 0.522 E^{6} = 0.68 + 0.522 = + 1.202 u$

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