Given that2C(s)+2O2(g)→CO2(g);ΔH=-787kJ ............. (i) H2(s)+12O2(g)→H2O(l);ΔH=-286 kJ ..............(ii) C2H2(s)+52O2(g)→2CO2(g)+2H2O(l);ΔH=-1301kJ.(iii)Heat of formation of acetylene is

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Given that
$2 C (s) + 2 O_{2} (g) \to {CO}_{2} (g); ΔH = - 787 kJ . . . . . . . . . . . . . (i) H_{2} (s) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); ΔH = - 286 kJ . . . . . . . . . . . . . . (ii) C_{2} H_{2} (s) + \frac{5}{2} O_{2} (g) \to 2 {CO}_{2} (g) + 2 H_{2} O (l); ΔH = - 1301 kJ . (iii)$
Heat of formation of acetylene is

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-1802 KJ

+1802 KJ

-800 KJ

+228 KJ

answer is D.

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$2 C (s) + H_{2} (g) \to C_{2} H_{2} (g)$

The heat of formation of this reaction can be calculated as:

Eq. (i) + eq. (ii) – eq. (iii)

Therefore, $ΔH = + 228 kJ$ .

Therefore, the correct option is D.

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