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Given that $2 {NO}_{2} ⇌ N_{2} O_{4}$ $Δ H =$ negative
The conditions at which the conversion of ${NO}_{2}$ to $N_{2} O_{4}$ becomes more and more are

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lower temperature and higher pressure

higher temperature and lower pressure

lower temperature and lower pressure

higher temperature and higher pressure

answer is B.

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Detailed Solution

$∆ H$ negative means exothermic. Hence, lower temperature and higher pressure $(a {asAy}_{g} = - 1)$ favours the formation of dimer.

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