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Q.

Given that a,b,c  are in AP.Then determinant x+1x+2x+ax+2x+3x+bx+3x+4x+c  in its simplest form is equal to

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a

x2+3ax+7c

b

0

c

15

d

10x2+5x+2c

answer is B.

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Detailed Solution

x+1x+2x+ax+2x+3x+bx+3x+4x+c 

Operate C1C1C 2

   =     -1x+2x+a-1x+3x+b-1x+4x+c

       =(1)1x+2x+a1x+3x+b1x+4x+c

Operate R2R2R1,R3R3R1

       =(1)1x+2x+a01b-a02c-a

      =(1)[c+a2b]=0   

                 [a,b,careinAP2b+a+c]

 

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