Given that A→ + B→ = C→ and that C→ is perpendicular to A→. Further if |A→| = |C→| , then what is the angle between A→ and B→?

A = Ctanθ = CA= 1⇒ θ = 450 = π4Angle between A→ and B→180-θ = 1800-45 = 1350 = 3π4 rad

Given that A→ + B→ = C→ and that C→ is perpendicular to A→. Further if |A→| = |C→| , then what is the angle between A→ and B→?

A = Ctanθ = CA= 1⇒ θ = 450 = π4Angle between A→ and B→180-θ = 1800-45 = 1350 = 3π4 rad

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Given that $\vec{A} + \vec{B} = \vec{C}$ and that $\vec{C}$ is perpendicular to $\vec{A}$ . Further if $| \vec{A} | = \vec{| C} |$ , then what is the angle between $\vec{A} and \vec{B}$ ?

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$\frac{π}{4} radian$

$\frac{π}{2} radian$

$\frac{3 π}{4} radian$

$π$ radian

answer is C.

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A = C

$tanθ = \frac{C}{A} = 1$

$\Rightarrow θ = 45^{0} = \frac{π}{4}$

Angle between $\vec{A} and \vec{B}$

180- $θ = 180^{0} - 45 = 135^{0} = \frac{3 π}{4} rad$

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Given that A→ + B→ = C→ and that C→ is perpendicular to A→. Further if |A→| = |C→| , then what is the angle between A→ and B→?

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Given that $\vec{A} + \vec{B} = \vec{C}$ and that $\vec{C}$ is perpendicular to $\vec{A}$ . Further if $| \vec{A} | = \vec{| C} |$ , then what is the angle between $\vec{A} and \vec{B}$ ?