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Q.

Given that m,n,s,t(0,);m+n=3;ms+nt=1;m,n are Constants and m<n . If the minimum value of s+t is 3+22 , point (m,n) is the midpoint of a chord of the ellipse  x24+y216=1 the equation of the line where the chord lies

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a

 x+y3=0

b

x2y+3=0

c

 4x+2y3=0

d

 2x+y4=0

answer is C.

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Detailed Solution

ms=sin2θ;      nt=cos2θ         s=mcosec2θ        t=nsec2θ

s+t=mcosec2θ+nsec2θ

=m+n+mcot2θ+ntan2θ

=3+m cot2θ+n+n+ntan2θUse  AmGm

3+2mn mn=2 m+n=3

m=1 n=2(m<n) Point is  (1,2)

uses S1=S11

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