Q.

Given the data at 25 °C Ag+I−→AgI+e− E∘=0.152V Ag→Ag++e− E∘=−0.800V

What is the value of log Ksp∘for Agl? (2.303 RT/IF = 0.059 V)

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a

-16.13

b

+8.612

c

-37.83

d

-8.12

answer is A.

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Detailed Solution

E° for the reactionAgI→Ag++I−  is  Ecell 0=(−0.800−0.152)V=−0.952V 

log⁡Ksp∘=Ecell∘RT/F=−0.952V0.052V=−16.13

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