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Q.

Given the data at 250C ,

Ag+IAgI+e;E0=+0.152 V

AgAg++e;E0=0.8 V

What is the value of log Ksp  for AgI  ?

(2.303RTF=0.059V)

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a

16.13

b

8.12

c

8.612

d

37.83

answer is A.

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Detailed Solution

GivenAgAg++e;E0=0.8(1)

Ag+IAgI+e;E0=+0.152(2)_

    (1)(2)AgIAg++I;E0=0.952V

                                   E0=2.303RTnF.logKsp

                             0.952=0.0591.logKsp

                             log.Ksp=0.9520.5916.108

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