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Q.

Given the family of lines, a(2x+y+4)+b(x2y3)=0.Among the lines of the family, the number of lines situated at a distance of 10 from the point M(2,3) is 

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a

2

b

1

c

0

d

answer is D.

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Detailed Solution

The point of intersection of the two lines are  (-1, -2).

Distance PM = 10

Hence the required line is one which passes through (1,2)  and is  to P.M.

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