Q.

Given the following informations.

(i) NH3(aq)+H2O(l)NH4+(aq)+OH(aq)        Kcl

(ii) CO2(g)+H2O(l)H2CO3(aq)       Kc2

(iii) H2CO3(aq)2H+(aq)+CO32(aq)         Kc3

(iv) H2O(l)H+(aq)+OH(aq)                     Kc4

The expression of Kc for 2NH3(aq)+CO2(g)+H2O(l)2NH4+(aq)+CO32(aq) will be equal to 

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a

Kc1Kc2Kc3/Kc4

b

Kc1Kc22Kc3/Kc42

c

Kc12Kc2Kc3/Kc42

d

Kc1Kc2/Kc3Kc4

answer is D.

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Detailed Solution

The given expression is obtained as 2Eq.(i) + Eq.(ii) + Eq.(iii)- 2Eq.(iv)

Hence  Kc=Kc12Kc2Kc3/Kc42 

The constant of equilibrium Kc is a constant that indicates how far a reaction will advance at a certain temperature.

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Given the following informations.(i) NH3(aq)+H2O(l)⇌NH4+(aq)+OH−(aq)        Kcl(ii) CO2(g)+H2O(l)⇌H2CO3(aq)       Kc2(iii) H2CO3(aq)⇌2H+(aq)+CO32−(aq)         Kc3(iv) H2O(l)⇌H+(aq)+OH−(aq)                     Kc4The expression of Kc for 2NH3(aq)+CO2(g)+H2O(l)⇌2NH4+(aq)+CO32−(aq) will be equal to