Given the polymers: A=Nylon; B= Buna-S; C=Polythene. Arrange these in increasing order of their intermolecular forces (lower to higher)

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B > C > A

C < A < B

B < C < A

A > B > C

answer is C.

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Detailed Solution

Nylon 6, 6 is fibre forming solid. It possess high tensile strength.
This characteristic can be attributed to the strong intermolecular forces like hydrogen bonding.
These strong forces also lead to close packing of chains and thus impart crystalline nature.
Elastomers or rubbers have the weakest intermolecular forces of attraction, while Polythenes are linear or slightly branched long chain molecules with intermediate intermolecular forces of attraction.
Hence, the increasing order of the intermolecular forces of the given polymers is as follows:

(i) Buna − S < polythene < Nylon 6, 6

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