Given the polymers: A=Nylon; B= Buna-S; C=Polythene. Arrange these in increasing order of their intermolecular forces (lower to higher)

• Nylon 6, 6 is fibre forming solid. It possess high tensile strength. 
• This characteristic can be attributed to the strong intermolecular forces like hydrogen bonding.
• These strong forces also lead to close packing of chains and thus impart crystalline nature.
• Elastomers or rubbers have the weakest intermolecular forces of attraction, while Polythenes are linear or slightly branched long chain molecules with intermediate intermolecular forces of attraction. 
• Hence, the increasing order of the intermolecular forces of the given polymers is as follows:

           (i) Buna − S < polythene < Nylon 6, 6