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Given the set of first n odd natural numbers. Five consecutive numbers are removed from first n odd natural numbers and the mean of remaining numbers is found to be $\frac{393}{5}$ .
Choose the correct option(s).

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The value of n can be 80

The value of n can be 75

The mean of removed number is 101

The mean of removed number is 99

answer is A, C.

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Detailed Solution

$n^{2} - 5 (2 n - 5) \leq \frac{393 (n - 5)}{5} \leq n^{2} - 25 \Rightarrow 73.6 \leq n \leq 83.6, n = 80 i s o n l y p o s s i b l e v a l u e$

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