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Q.

Given the thermochemical equations:

Br2(l)+F2(g)⟶2BrF′(g)   ΔH∘=−188kJ

Br2(l)+3F2(g)⟶2BrF3(g)  ΔH∘=−768kJ

determine ΔH∘ for the reaction

BrF(g)+F2(g)⟶BrF3(g)

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a

−290kJ

b

−478kJ

c

−956kJ

d

−580kJ

answer is D.

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Detailed Solution

For the reactions

Bv2(l)+F2(9)→2BrF(g);−1886J/mol−12

Bv2(l)+3F2(α)→2BrF3 (g);−7686kJ/mol

ΔH∘=[−768+188]×12=−290kJ

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